13. Roman to Integer
Roman to Integer
Roman numerals are represented by seven different symbols: I
, V
, X
, L
, C
, D
and M
.
Symbol Value
I 1
V 5
X 10
L 50
C 100
D 500
M 1000
For example, 2
is written as II
in Roman numeral, just two ones added together. 12
is written as XII
, which is simply X + II
. The number 27
is written as XXVII
, which is XX + V + II
.
Roman numerals are usually written from largest to smallest from left to right. However, the numeral for four is not IIII
. Instead, the number four is written as IV
. Because the one is before the five we subtract it making four. The same principle applies to the number nine, which is written as IX
. There are six instances where subtraction is used:
I
can be placed beforeV
(5) andX
(10) to make 4 and 9.X
can be placed beforeL
(50) andC
(100) to make 40 and 90.C
can be placed beforeD
(500) andM
(1000) to make 400 and 900.
Given a roman numeral, convert it to an integer.
Example 1:
Input: s = "III"
Output: 3
Explanation: III = 3.
Example 2:
Input: s = "LVIII"
Output: 58
Explanation: L = 50, V= 5, III = 3.
Example 3:
Input: s = "MCMXCIV"
Output: 1994
Explanation: M = 1000, CM = 900, XC = 90 and IV = 4.
Constraints:
1 <= s.length <= 15
s
contains only the characters('I', 'V', 'X', 'L', 'C', 'D', 'M')
.- It is guaranteed that
s
is a valid roman numeral in the range[1, 3999]
.
For this super simple solution, we loop through the characters of the provided string, and for each one, we check whether that character is worth more or less than the next one (if the next one exists).
If it’s worth less, that means it is a deduction (for example, in the string “IV”, “I” is worth less (1) than “V” (5), so it is a deduction), and so this value is removed from the overall total.
Otherwise, it’s considered an addition, and added to the total:
Let`s Code It!
var romanToInt = function (string) {
const numerals = {
I: 1,
V: 5,
X: 10,
L: 50,
C: 100,
D: 500,
M: 1000,
};
const strLen = string.length;
let total = 0;
// Loop through the letters
for (let i = 0; i < strLen; i++) {
// Check if the current letter is followed by one with a higher value (indicating a deduction)
if (i < strLen - 1 && numerals[string[i + 1]] > numerals[string[i]]) {
// Remove the current letter's numeric value from the total
total -= numerals[string[i]];
} else {
// Add the current letter's numeric value to the total
total += numerals[string[i]];
}
}
return total;
};
That’s all folks! In this post, we solved LeetCode problem #13. Roman to Integer
I hope you have enjoyed this post. Feel free to share your thoughts on this.
You can find the complete source code on my GitHub repository. If you like what you learn. feel free to fork 🔪 and star ⭐ it.
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Happy coding!
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